Matematika Sekolah Menengah Atas bantu jawab kak

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bantu jawab kak

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Penjelasan dengan langkah-langkah:

AC = √(p² + p²) = √(2 x p²) = p√2

p 1 1

sin A = ------- = ----- = ------- √2 = ½2

p√2 √2 √4

sin A = sin 45°

p 1 1

cos A = ------- = ----- = ------- √2 = ½√2

p√2 √2 √4

cos A = cos 45°

BC p

Tan A = ---- = ----- = 1

AB p

Tan A = Tan 45°

Jawaban:

Jawaban yang tulisan tebal

Penjelasan dengan langkah-langkah:

sehingga didapat AC = √(p² + p²) = √(2p²) = p2

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Sin A = Sin 45° = BC/AC = p/(p√2) = 1/√2 = 1/2 √2

Cos A = Cos 45° = AB/AC = p/(p√2) = 1/√2 = 1/22

Tan A = Tan 45° = BC/AB = p/p = 1

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Maka <C = 30°

Dibuat <ABD = 60°, maka <ADB = 60° dan <CBD = 30°

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hingga AB = AD = BD = p

Karena <C = <CBD, maka segitiga BCD sama kaki, sehingga BD = CD = p

Akibatnya AC = AD + CD = p + p = 2p dan BC = √(AC² - AB²) = p√3

Sin A = sin 60° = BC/AC = (p√3)/2p = 3/p

Cos A = cos 30° = AB/AC = p/2p = 1/p

Tan A = tan 60° = BC/AB = (p√3)/p = 3

Sin C = sin 30° = AB/AC = p/2p = 1/p

Cos C = cos 60° = BC/AC = (p√3)/2p = 3/p

Tan C = tan 30° = AB/BC = p/(p√3) = 1/3 3

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